Question

The velocity (in meters/sec) of a particle moving along a straight line is given by v(t)=3t^2+2t+3, where t is measured in seconds.
Answer the following questions given that the initial positions(0)=6.
a. What is the meter position of the particle at any given time t?
b. What is the meter position of the body at time t=2?
c.What is the meter position of the particle at time t=10?
d. What is the displacement of the particle on the time interval 2 15 years ago

Answer 1

part a) you integrate the velocity function to obtain the position function, keep in mind initial position
part b) use function from part a) and plug in t=2
part c) same as before use t =10
part d) this is how far the particle has moved so f(10) - f(2)

Answer 2

We haven't gotten to integrals yet in class.. Exactly how do I do that?

Answer 3

hmm i guess you could graph the velocity function and estimate the area under the graph from 2 to 10. that would answer part d)

Answer 4

you could also estimate position using the velocity at each t.
so p(0) = 6 and v(0) = 3
then p(1) = 9 you assume particle moved 3meters that first second
find v(1) to get p(2) and so on..
*p(t) is position

Answer 5

I've already got it. Thanks though :)