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find lcm of y^2-81, 9y+81
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The multiples in y^2-81 are\[y^2-81=(y-9)(y+9)\]since this is a difference of two squares. The multiples of 9y+81 are\[9(y+9)\]You'll notice that the only multiple the two numbers (expressions) have in common is (y+9), so \[y+9\]is your LCM.
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anyone here from Carnegie Mellon University?
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No, sorry.
no prob... just found this site randomly
haha, me too...
so, are you staff here? I mean you got this HERO status
no, not staff, just answered a lot of questions :)
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alright, well, good luck :) I just got one fan, even though I did not do anything or help anyone, strange :)
lol, take what you can get!
haha :) yeah.. i always take everything I can
alright guyz, i came, i saw, and now its time to leave, see you next time
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