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Mathematics 9 Online
OpenStudy (anonymous):

simplify the expression x^6y^3/x^3y

OpenStudy (anonymous):

x^(3y*(y^2 -1) is it just a part of the task?

OpenStudy (anonymous):

\[x ^{6y ^{3}}/x ^{3y}\] ?

OpenStudy (anonymous):

or \[x ^{(6y)^{3}}/x ^{3y}\]

OpenStudy (anonymous):

hmm good question - forgot the other possibility :P

OpenStudy (anonymous):

the 1st one

OpenStudy (anonymous):

mine should be right :P

OpenStudy (anonymous):

its not your sorry=) but its peddani the 1st one

OpenStudy (anonymous):

i know that you answered to peddani - my first answer should be the simplification of the first one of peddani just add a bracket in the end

OpenStudy (anonymous):

i dont get it

OpenStudy (anonymous):

x^2/x^3 = x^(2-3) so is x^6y^3/x^3y equal to: x^[(6y^3)-3y] then you can factorise 3y: x^[3y (2y^2 - 1)] but what do you need a simplification for?

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