Question

solve by the elimination method

0.3x - 0.2y=4

0.5x + 0.3y = 71/23

Answer 1

yikes!! thats scary :)

Answer 2

0.3x-0.2y=4
0.5x+0.3y=71/23

so, first you have to get rid of the y from both equations

Answer 3

right! i'm clueless, the fraction throws me off!

Answer 4

It is simple:

multiply both equations, so that the y members of both of them are eliminated when added

so in your case, we can multiply the first equation by 3, to get 0.9x-0.6y=12

and now we need to multiply the second equation in such a way that when coresponding members of both of them are added, y is eliminated (equals zero)

so, we have to multiply it by 2 to get 1x+0.6y=142/23

Answer 5

now, we have to add all coresponding members to eliminate y, so

0.9x-0.6y=12
+ 1x+0.6y=142/23
_________________________
1.9x+0=418/23

=1.9x=418/23

Answer 6

ok, i follow you so far ....

Answer 7

so, now lets solve for x

1.9x=418/23
23*1.9x=418
43.7x=418
x=418/43.7
x=9.56521

Answer 8

i have to solve it as a fraction, so i'm plugging in 418/43.7 to solve for y ....

Answer 9

now to get y we just take any equation, and substitute x into it, and solve for y

0.3x-0.2y=4
0.3*9.56521-0.2y=4
2.869565217-0.2y=4
-0.2y=4-2.869565217
-0.2y=1.130434
y=1.130434/-0.2
y=-5.65

Answer 10

if I helped in anyway, I would apreciate if you would fan me (reload this page, and click a blue Become a fan button near my name)

Answer 11

x~~9.56522, y~~-5.65217

Answer 12

yes, thats correct

Answer 13

what is y as a fraction?

Answer 14

that is y as a decimal

Answer 15

my answer has to be in the form of a fraction

Answer 16

to get it as a fraction, just do same steps as I showed you, just keep pluging in fractions all the way from the beginning until now, and you can get a fraction

Answer 17

x=220/23

Answer 18

ok, thx! and i became a fan while you were working on my problem, thx!

Answer 19

y=-130/23

Answer 20

Got the fraction?

Answer 21

x=220/23
y=-130/23

Answer 22

great, thx!

Answer 23

You are welcome, and look at the plot that will help you understand

Answer 24

If you any more problems, you can send it my way, I will be happy to answer

Answer 25

great, thx for your help!