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Mathematics 11 Online
OpenStudy (anonymous):

lim x approaches 1 x-1/x^2+6x-7

OpenStudy (amistre64):

is that x-1 on top of the rest? if so, try to use () to enclose the top and bottom parts...just makes it easier to read

OpenStudy (amistre64):

(x-1)/(x^2+6x-7) as x->1 we of course get an indeterminate number 0/0

OpenStudy (amistre64):

we should factor the bottom and see if that will elimiate some "problem" areas

OpenStudy (anonymous):

on top

OpenStudy (amistre64):

(x-1) --------- we see whats going on now (x+7)(x-1)

OpenStudy (anonymous):

Exactly got the same thing by factoring

OpenStudy (amistre64):

at x=1 there is a "hole" in the graph:

OpenStudy (amistre64):

so the limit actually "approaches" 1/8 if we cancel terms and apply the limit

OpenStudy (anonymous):

Ah ok I follow.

OpenStudy (amistre64):

the graphs for 1/(x+7) and the one you wrote are the same except for one point....x=1 has a "hole" in yours, that isnt there in this one....

OpenStudy (anonymous):

Yeah I see that .

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