Question

Find f'(x), f(x) = (x^2 - 2x - 6)^3

Answer 1

Just don't forget your chain rule and you should be fine.

Answer 2

Did you try it yet?

Answer 3

ok, i'll try it, just a sec

Answer 4

Any luck?

Answer 5

i got (2x - 2) and 3u^2, and now?

Answer 6

OH, WAIT! i'm a idiot. just a sec.

Answer 7

\[3(x^2-2x-6)^2(2x-2)\] Looks right to me (assuming you have u = x^2-2x-6 )

Answer 8

ahh, ok, but now i'm stuck.

Answer 9

what's the next step?

Answer 10

that's it

Answer 11

there is no way to simplify?

Answer 12

No good simplification. The quadratic is not nicely factored and it has that nasty square, so I'd just leave it that way.

Answer 13

Ahhhh! THANKS! :D