Question

does anyone understand double integrals in polar??

Answer 1

yes

Answer 2

I can think of several people who do actually.

Answer 3

okay
can you help with the following problem?
use polar coordinates to find the volume of the given solid: above the disk \[{x ^{2}+y ^{2} \le4}\] and under the cone z=\[\sqrt{x ^{2}+y ^{2}}\]

Answer 4

Yes. Just replace \(x^2 + y^2\) with \(r^2\) and integrate from \(0 \le r \le 2\)

Answer 5

why 0 to 2 and not -2 to 2. if you look at the disk isn't a circle with center (0,0) and radius 2?