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OpenStudy (anonymous):
what is meant by the term 'proportional'.
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OpenStudy (anonymous):
two terms are proportional if one is the constant multiple of the other
OpenStudy (anonymous):
what if increasing the value of x, y also increases.....or if y decreases???
OpenStudy (anonymous):
in such case x and y are directly proportional
y = k x where k is constant of proportioanlity
OpenStudy (anonymous):
if on increasing x , value of y decreases...4 xample
y=c-mx.......then ????
OpenStudy (anonymous):
then both are inverse propotional, y = 1/k xor k = yx
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OpenStudy (anonymous):
mam ...u speak hindi???
OpenStudy (anonymous):
yup
OpenStudy (anonymous):
but my insti teacher do not agree with this point so i think we r going wrong.......
OpenStudy (anonymous):
whats wrong in that?
OpenStudy (anonymous):
kuch alag logic lagna chaaiye mere khyal se!!!!!!
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OpenStudy (anonymous):
be more precise........i mean apna pont clear kuro,actual prob kya hy
OpenStudy (anonymous):
direct proportion main we get the same ratio for every quotient x/y
OpenStudy (anonymous):
what u said is inverse variation...and thats not the case .imean answer
OpenStudy (anonymous):
can u put an exp?
OpenStudy (anonymous):
y=c-mx
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OpenStudy (anonymous):
c is a constant?
OpenStudy (anonymous):
yup
OpenStudy (anonymous):
slpoe-intrcept form equation...
OpenStudy (anonymous):
c u later ...bye
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