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Mathematics 16 Online
OpenStudy (anonymous):

what is meant by the term 'proportional'.

OpenStudy (anonymous):

two terms are proportional if one is the constant multiple of the other

OpenStudy (anonymous):

what if increasing the value of x, y also increases.....or if y decreases???

OpenStudy (anonymous):

in such case x and y are directly proportional y = k x where k is constant of proportioanlity

OpenStudy (anonymous):

if on increasing x , value of y decreases...4 xample y=c-mx.......then ????

OpenStudy (anonymous):

then both are inverse propotional, y = 1/k xor k = yx

OpenStudy (anonymous):

mam ...u speak hindi???

OpenStudy (anonymous):

yup

OpenStudy (anonymous):

but my insti teacher do not agree with this point so i think we r going wrong.......

OpenStudy (anonymous):

whats wrong in that?

OpenStudy (anonymous):

kuch alag logic lagna chaaiye mere khyal se!!!!!!

OpenStudy (anonymous):

be more precise........i mean apna pont clear kuro,actual prob kya hy

OpenStudy (anonymous):

direct proportion main we get the same ratio for every quotient x/y

OpenStudy (anonymous):

what u said is inverse variation...and thats not the case .imean answer

OpenStudy (anonymous):

can u put an exp?

OpenStudy (anonymous):

y=c-mx

OpenStudy (anonymous):

c is a constant?

OpenStudy (anonymous):

yup

OpenStudy (anonymous):

slpoe-intrcept form equation...

OpenStudy (anonymous):

c u later ...bye

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