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Mathematics 6 Online
OpenStudy (anonymous):

hello anyone can hel[p me

OpenStudy (anonymous):

what do you need help with?

OpenStudy (anonymous):

n2-n for n =5 \[n2-n for n =5\]

OpenStudy (anonymous):

ok so just plug in 5 for n

OpenStudy (anonymous):

do you mean \[n^2-n\]

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

ok so if you plug in 5 for n it will look like this: \[5^2-5\] \[5^2=25\] 25-5=20

OpenStudy (anonymous):

when=5 ,n2 - n = ____ 2 u put under the line

OpenStudy (anonymous):

I'm a little confused as to what you are asking let's go to http://www.dabbleboard.com/draw?b=Guest650426&i=0&c=696cc42c34658c69ab2d66582d499fca37aaae0d and then you can draw out your problem on the white board and I can help you better

OpenStudy (anonymous):

just type in the chat box when you are there

OpenStudy (anonymous):

do anyone no this answer 5(x+3) =

OpenStudy (anonymous):

do anyone no this answer 5(x+3) =

OpenStudy (anonymous):

So you have to expand the problem first. You do this by multiplying both of the numbers in the parenthesis by 5 and setting it equal to 0. 5(x+3) 5x+15=0 subtract 15 from both sides 5x=-15 divide both sides by 5 x=-3

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