Question

How would you fine the square root of this number: 3square root of 28?

Answer 1

Is this 3*Sqrt(28)?

Answer 2

I think so I'm doing a worksheet and I'm trying to workout the problem the answer is suppoed to 6 square root of 7

Answer 3

3sqrt(28)=3sqrt(4*7)=3sqrt((2^2)*7)=3sqrt(2^2)sqrt(7)=3*2*sqrt7=6sqrt7

Answer 4

How would you do the square root of this problem: -3 square root of 54. The answer is supposed to be -9 square root of 6.

Answer 5

can you write 54 into product of prime numbers (1,2,3,5,7,11,....) for me?

Answer 6

2,3,3,3

Answer 7

my computer went crazy sorry for so many entries

Answer 8

ok, there you have 54=2x3x3x3.
there is a rule like this: sqrt(a^2)=a, a>0
so you have 54=2x3x3^2
sqrt54=sqrt(2x3x3^2)=sqrt(2x3) x sqrt(3^2)
you do the rest for me?
the thing here is you need to understand how it work, then you can do any problem

Answer 9

I don't understand what you want me to do?

Answer 10

-.-
\[-3\sqrt{54}=-3\sqrt{2*3*3^{2}}=-3\sqrt{6}\sqrt{3^{2}}=-3*3*\sqrt{6}=-9\sqrt{6}\]

Answer 11

but you still have to understand the method

Answer 12

I understand how you factored it down but how do you get the answer of -9 square root of 6?

Answer 13

√(3^2)=3, you understand this right?
so√(54)=√(2*3*3^3)=√(6*3^3)=(√6)*(√3^3)=(√6)*3
then -3*√(54)=-3*(√6)*3=-3*3*(√6)=-9√6
clear?