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x^2 + 3x - 28 = 0
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please answer this!
Factor it first.
my math teacher said not to factor first :/
Have you learned the quadratic formula?
yeaa
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\[x = \frac{-b \pm \sqrt{b^2-4ac}}{2a}\] In this case a =1 , b = 3 and c = -28
like i no how to get this far. x^2 + 3x = 28 and i no that is the first step, then, you are supposed to cut the 3x in half and square it. but im confused because it is a prime and odd number!
What are you trying to achieve with that equation? Are you trying to find the zeros?
im trying to find the x and the directions say " solve by completing the square."
ahhh there you go now we can do something with that.
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Visit this site. Hope it helps. http://www.purplemath.com/modules/sqrquad.htm
k thanks!
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