Question

f"(x)=4x-3 and f'(-3)=-1 and f(-3)=0
find f'(x) and f(1)

Answer 1

do you know integrals?

Answer 2

is that the same as antiderivatives

Answer 3

f'(x)=(4(x^2))/2 + 3x + c= 2x^2 + 3x + c
then use f'(3)=-1=2(3)^2 + 3(3)+c to solve for c=-28
f(x)=(2/3)x^3 + (3/2)x^2 +28x +c

Answer 4

now see if you can use f(-3)=0 to find c again and then find f(1)

Answer 5

i got the same answer but it tells me that f'(x) is wrong...