Help with trigonometry identities please! Simplify: a) cos(180º +x) + cos(180º - x) b) cos(7pi/126º)cos(36º/5)+sin(7pi/126º)sin(36º/5)
cos(a+b) - cos(a-b): cos^2(a) - sin^2(a) + cos^2(a) + sin^2(a) 2cos^2(a) 2cos^2(180) ; cos(180) = -1 2(-1^2) = 2(1) = 2
\[7\pi/126^O\] ????
if anything that would equal 7pi(180)/126pi ... but ive never seen anything written like that before.
this is the equation:
well, its a cos(a-b) construct, but i dunno about those digits
if you convert the degrees to radians, then I spoose you can have a radian measure without a pi in it.... but its just unnatural :)
ok..thanks for the help on the first one
7pi = 180 degrees, lets substitute that in instead
cos(180/126)cos(36/5) + sin(180/126º)sin(36/5)
then cos(180/126 - 36/5) is your angle....
add the fractions and simplify... right?
3636 ----- 630
602/105...whats our remainder?
did u already multiply the fraction by cos? im confused, sorry :S
5 + (77/105)
you dont need to do that :) you just need to find the angle of the cos: cos(a - b); find a - b
108(5) 36(126) ------ - -------- 126(5) 126(5)
180(5) 36(126) ------ - -------- 126(5) 126(5) arghh!!..typoed it lol
3636 cos of ----- is what I get 630
-3636 ------ you gotta catch this stuff, cause I dont always ;) 630
Amistre please help :'(
that looked alot better in my head lol
loco..... give me a sec; im on break ;)
ok
im not about to catch anything lol. i am very confused by trig in general..im about to post a question on trig identities...could u maybe help me through those when i post it? u seem like u know what ur doing :)
its a farse, I no nutheeenng!!!
he does. he know his stuff :)
ur a superhero for a reason :)
pfftt!!!.....super hero, now I gotta wear tights, and that aint a pretty picture ;)
I get an angle of -5.77 degrees when we do all that.
that is if its even right lol
the cos of that angle = .9949 and thats the best I got fer ya on that one....right or wrong ;)
r u solving the whole question btw? i just need to simplify..
I solved it for the angle; andle = 5 + (77/105) and for the value of the cosine of that angle :=: .9949 how to simplify it is beyond me :)
:'( ok. that's better than no answer at least!
well, -5 and 77/105ths.... but yeah :) ..good luck with it; if anything, get it wrong and move ahead :)
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