Question

y=4x^ +8x +3
What are x intercepts and Y intercept

Answer 1

the last number is your y intercept: that +3. (0,3)

Answer 2

you solve for the equation = 0 to get your x interecpts

Answer 3

4x^2 +8x +3 = 0

4(3) = 12

1,12;2,6...2 and 6 work well.

(x+6)(x+2) = 0 when either x+6 = 0 or when x+2 = 0

Answer 4

your x intercepts are: (-6,0) (-3,0)

Answer 5

what would be my vertex then?

Answer 6

Vertex is at x = -b/2a which is -8/(2*4) = -1
so plug in x = -1 and you get
y = 4(-1)^2 + 8(-1) + 3 which is -1

So your vertex is at (-1,-1)

Answer 7

yeah, your vertex is simply halfway between your x intercepts

Answer 8

hmmm...... i forgot to divide out my 4 again......

(x+6/4) (x+2/4)

(x+3/2)(x+1/2) your x intercepts are (0,-3/2) (0,-1/2)

Answer 9

you gotta let me know when I make a mistake...im not always gonna be around to catch these things lol

Answer 10

like this blunder o'mine "(0,-3/2) (0,-1/2)"

it should be (-3/2,0) (-1/2,0) brains going faster than my fingers can keep up :)