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OpenStudy (linda):
how do you subtract these? negative square root of 3 over 2 - square root of 3 over 3
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OpenStudy (anonymous):
time both numerator and denominator of the first fraction with 3 and the second with 2. Try it.
OpenStudy (anonymous):
depends. if you are talking about an unsimplified root first simplify the root by multiplying top and bottom with the certain root
OpenStudy (anonymous):
if you have sqrt(3/2), then multiply top and bottom by sqrt(2)
you get sqrt(6)/2
OpenStudy (anonymous):
could be, not quite clear with the question
OpenStudy (anonymous):
I would assume -sqrt(3) sqrt(3)
------ - ------
2 3
Correct?
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OpenStudy (anonymous):
If so... you need a common denominator of 6
-3sqrt(3) 3sqrt(3)
-------- - -------
6 6
-6 sqrt(3)
---------
6
-sqrt(3) as the answer
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