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solve 1-x=x ---- x
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You can solve this by multiplying both sides by x and then adding x and subtracting 1 to get x^2+x-1=0 which you can solve by plugging it into your calculator or using the quadratic formula
would it be posible to show this using the numbers and the variables so i can understand it better
sure \[(1-x)/x =x\] \[x * (1-x)/x = x * x \] \[1-x = x^2\] \[1-x - 1 + x= x^2 +x -1\] Everything cancels out to get \[x^2+x-1=0\] Hope this helps!
sorry, but how did you get 1-x-1+x=x^2+x-1
That's a perfectly fine question to ask. I just subtracted 1 and added x to both sides of the equation.
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