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Mathematics 16 Online
OpenStudy (anonymous):

solve 1-x=x ---- x

OpenStudy (anonymous):

You can solve this by multiplying both sides by x and then adding x and subtracting 1 to get x^2+x-1=0 which you can solve by plugging it into your calculator or using the quadratic formula

OpenStudy (anonymous):

would it be posible to show this using the numbers and the variables so i can understand it better

OpenStudy (anonymous):

sure \[(1-x)/x =x\] \[x * (1-x)/x = x * x \] \[1-x = x^2\] \[1-x - 1 + x= x^2 +x -1\] Everything cancels out to get \[x^2+x-1=0\] Hope this helps!

OpenStudy (anonymous):

sorry, but how did you get 1-x-1+x=x^2+x-1

OpenStudy (anonymous):

That's a perfectly fine question to ask. I just subtracted 1 and added x to both sides of the equation.

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