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simplify 4 over the square root of 2 plus the square root of 3
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is the sq rt of 3 under the fraction or out beside it?
under
then multiply by the numerator and denominator by the congugate which is sq rt 2 MINUS sq rt 3
that would give you 4(sq rt 2 - sq rt 3) in the numerator and (sq rt 2 + sq rt 3)(sq rt 2 - sq rt 3) in the demoninator
thx
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you're welcome. once you do that and simplify, I think you'll have to multiply by the new congugate to finish it
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