Question

find the perimeter of a rectangular object with the length of (square root 75) feet and the width (square root 48 feet)???????????????

Answer 1

perimeter is the total length of all the edges of the object
so P=2*sqrt(75)+2*sqrt(48)
P=2*sqrt(3*25)+2*sqrt(3*16)
P=2*5sqrt(3)+2*4sqrt(3)
P=10sqrt(3)+8sqrt(3)
P=18sqrt(3)

Answer 2

is that how to do it or the answer?

Answer 3

that's how to do it. but if you struggle with changing sqrt(75) ans sqrt48 into simpler form then I can get you more detail

Answer 4

ok, so i think you have problem with that.
sqrt = square root

sqrt(75)=sqrt(3*5*5)=sqrt(3*5^2)=sqrt(3)*sqrt(5^2)=5*sqrt(3)
48 is similar

Answer 5

i dont get what the peremiter would be tho of the two ?

Answer 6

rectangular has 2 longer edges and 2 shorter edges
Perimeter = total lengths of 2 longer edges + total length of 2 shorter edges
you know the longer edge is sqrt75 ft and shorter edge is sqrt48 ft, so parameter:
P= sqrt75 + sqrt75 + sqrt48 +sqrt48 = 2sqrt75 + 2sqrt48

Answer 7

rectangle lol

Answer 8

so it would be 5 sqrt 3 plus 5 sqrt 3 plus 4 sqrt 3 or something

Answer 9

5 sqrt 3 plus 5 sqrt 3 plus 4 sqrt 3 plus 4 sqrt 3 since 2 edges each.

Answer 10

do i add them together for the answer

Answer 11

yeah, you will get 18 sqrt3

Answer 12

thanks so much

Answer 13

no problem, as long as you understand how it works, there shouldn't be any other problems

Answer 14

nope do you no what a house would look like if using those measures

Answer 15

what do you mean? the base should be a nice squared rectangle