Question

how do u solve by factoring, completing the sqaure or using the quadratic formula on this problem
x^2-8x=5

Answer 1

x^(2-8x) ?

Answer 2

For factoring set it equal to zero
->x^2 -8x -5 = 0
Then see if any factors of -5 add up to -8 if there are none it is prime
For completing the square, take half of -8 which is -4 and square it subtract that from -5
_> x^2-8x-5 = (x-4)^2-5-(-4)^2 = (x-4)^2 -21 = 0
For quadratic formula which really is the same as completing the square use the formula x = -b +-sqrt(b^2-4ac)/2a

Answer 3

k thank you soooo much
i used the completeting the sqaure. so thats the answer

Answer 4

once you solve for x yes
(x-4)^2 = 21
x-4 = sqrt(21)
x= 4 +- sqrt(21)