Let the reproductive rates in four successive generations of a population be 4,2,3,2. If the population has a size of 10 million individuals at the end of this four-generation period, how large will it be after another two generations if there is no regulation of growth? Carrying capacity is 100 million.
do you expect the pattern to continue? 4,2,3,2,2,2...
after another 2 generation
ok so then after the next generation with a reproductive rate of 2 it would grow 200% to 30 million ->10(1+2) = 30 Repeating this for the next generation 30(1+2) = 90 90 million is that right?
take note with the carrying capacity
dn1/dt=r1n1
\[dn2/dt =r2n2\]
the rate of increase of the total population is \[dN/dt =r1n1+r2n2 = mean of the r's(N)\]
does n1 refer to initial population, n2 second generation and r1 is reproductive rate
Let N be the total population number; N = n1 + n2.
yes
ok
is this for a differential equations class
get the mean of the r
the mean of the rates is 15/6 for all generations, how does that help? im sorry im not following or helping you :(
either
dn2/dt=n2(r2-mean of r (N)/K K is the carrying capacity
so dn2/dt = n2(2 - 15/6) / 100 mill ->dn2/dt = -n2/200 what is n2?
if we integrate both sides and solve for n2 -> n2 = e^-t/200
ok
but the problem only refers to generations not time, so to get a number for n we need a t ??
do you know the answer?
we only have one strain n
ok well i gotta go, good luck hope you find someone to help you sorry
thank you very much, take care and GOD BLESS
your a great help, thanks a lot
bye
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