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hw do u solve 6-p under square root sign =p?
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you mean√6-p = p. so 6-p=p^2.(p≤6) p^2+p-6=0.(p≤6) (p+3)(p-2)=0.(p≤6) p1=-3,p2=2.
no the -p is also under the square root sign
so √6-p = √p , is that what you mean?
i've got it right . √(6-p) = p. so 6-p=p^2.(p≤6) p^2+p-6=0.(p≤6) (p+3)(p-2)=0.(p≤6) p1=-3,p2=2.
no like the square root sign over 6-p and =p out of it
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yes, the answer is correct, p= -3 or 2.
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