Question

Solve the differential equation (x^2 + 1)y' = xy. Am having trouble separating the equation to dy/dx = g(x) h(y) format

Answer 1

y' is dy/dx. So divide by (x^2)+1, swing to other side.

Answer 2

This seems to leave me me with xy dx = x^2 + 1 dy, I'm stumped as to how to get the y from the xy dx onto the dy side and vice versa with the x^2+1

Answer 3

found a solution, thanks