Question

Please help me solve:
Integral of dy / [ sqrt(y^2 + 4y) ]

Answer 1

I know I have to use trig substitution. But I dunno with this one

Answer 2

im stuck on this one as well
you can complete the square to get (y+2)^2 - 4
but thats of the form 1/sqrt(x^2 - 1) which there is no trig substitution to help us
try factoring out a negative but then its still in square root
sorry ??

Answer 3

I get it. I used \[\sec \theta\]