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OpenStudy (anonymous):
solve for x and y by substitution: x/3+y/4=2 2x/3-y/2=0
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OpenStudy (anonymous):
SOMEONE PLEASE HELP ! =(
OpenStudy (anonymous):
working on it
OpenStudy (anonymous):
thanks!
OpenStudy (anonymous):
simplify the first one then the second
OpenStudy (anonymous):
the first one comes out to be 4x-3y=24
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OpenStudy (anonymous):
the second comes out to be 4x-3y=0
OpenStudy (anonymous):
where on earth do you find the 24 from? :S
OpenStudy (anonymous):
it becomes 4x/12 + 3y/12 = 2
OpenStudy (anonymous):
its the lcm of 3 and 4 and then multiplied by 2 on right hand side
OpenStudy (anonymous):
then simplifies to 4x+3y=24
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OpenStudy (anonymous):
4x-3y=2 -4x-3y=0
OpenStudy (anonymous):
same thing as 4x-3y=24 -4x+3y=0
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