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Mathematics 12 Online
OpenStudy (anonymous):

how can i evaluate log2(thats a little 2)160-log2(little 2)5 without using a calculator?

OpenStudy (anonymous):

ok, so when you subtract to logs, it's like dividing the numbers you are taking the logs of

OpenStudy (anonymous):

so, log2(x) - log2(y) is the same as log2(x/y)

OpenStudy (anonymous):

log(base 2)160-log(base 2)5=log(base 2)32, as mindedone said. therefore, ask yourself 2 to what power is 32.

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