Mathematics
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OpenStudy (anonymous):
simplify the square root of 8n-27 devided by 4-n
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OpenStudy (anonymous):
kstatefan, do you know how to divide polynomials involving variables yet or no?
myininaya (myininaya):
-8-27/(4-n)
OpenStudy (anonymous):
I can show you if you need me to kstatefan. Just trying to assess how much I should go into detail
myininaya (myininaya):
what is 8n/(-n) simplify to
OpenStudy (anonymous):
-8 right?
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myininaya (myininaya):
yes
myininaya (myininaya):
put that where the quotient goes and then multiply by the divisor to figure out what you need to subtract
OpenStudy (anonymous):
k
myininaya (myininaya):
oops i got the wrong remainder above
myininaya (myininaya):
-8+5/(4-n)
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myininaya (myininaya):
so we have (8n-27)-(8n-32) which is ...
OpenStudy (anonymous):
this is exponential and logarithmic functions we arent doing this right
myininaya (myininaya):
oh thats the sqrt(8n-27)
myininaya (myininaya):
i didnt see the sqrt sorry
myininaya (myininaya):
so we aren't dividing. I would say it is already simplified
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myininaya (myininaya):
how do you use log or exponentiation here
myininaya (myininaya):
exponential*
OpenStudy (anonymous):
and i said it wrong the funtion is actually\[\sqrt{(8^{n}-27)\div (4^{-n})}\]
OpenStudy (anonymous):
and i have no idea
myininaya (myininaya):
=\[\sqrt{8^n*4^n-27(4^n)}=\sqrt{32^n-27(4^n)}\]
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myininaya (myininaya):
\[\sqrt{4^n}*\sqrt{(8^n-27})=2^n*\sqrt{(8^n-27)} \]