f(x)=-2/x^2+2x-3 Determine the domain of the function
domain is negative infinity to infinity but there should be some vertical asymptotes in there so it is not continuously from negative infinity to infinity. gimme a sec
x cannot be 0
no dumbcow, x cannot be -3 or 1
domain should be x not equal to -1 or -3 i.e R-{-1,-3}
oh whoa nevermind didnt see the negative sign in front of the 2
and R here is the set of real numbers:)
got it?
x cannot be 0 thats it so all real numbers except when x is 0
I'm trying. lol. Thank you for explaining; I sure do appreciate it. Got tons of this stuff to help someone else out.
it doesnt make sense even if x=0 as there is a '-3' in th e denominator ...lol
this is unbelievable i must be drunk final answer is all real numbers except when x equals to 1 or -3
All numbers except wen x=-1 or -3....
of course x can equal to 0!!!!!!
no its 1 or -3 not -1 or -3
haha sorry you guys didnt read the problem correctly
yes it can be =0
yep
@dumbcow haha i hadnt the first time around either
now did u get it??
hello anybody there??
yes
so u got what i typed above?
Okay, so the domain is not (-inf, inf).....
no its not
So it's all real numbers except when x=0
no...its all real nos. except wen x=-1 or x=-3
now , is it alright?
Yes, thank you
you're welcome @JJ
So, if I had [f(x)=\sqrt{5-x}\] , would that mean, the Domain would be all real numbers? Just making sure I got that one right.I'm assuming this because I can plug anything in there.
no x cannot equal any negative number in that caase
u can plug anything there except the number/numbers that make the denominator go '0'
and yeah , sqrt can't be negative so u have to remeber that:) so domain wud be numbers<5
So, all real number <5
thinker i think youre a bit confused. x can equal indeed to 5, that would just mean y equals 0. The domain is R = (0,infinity)
I sure am confused. So sorry.
JJSONFIRE i am really off it today listen to thinker im wrong
Hey, trust me I understand.
yep youre right
hey ....if its(),infinity) that wud make the sqrt tern negative which is not Real!!
i know you do im admitting that im wrong. im tired but still willing to help
i just explained to you that i made a mistake
ive been working all day..... :/
yeah..thats ok...im tired too...nevermind
Do you think you guys could help me with one more..please
sure
This set of problems says I need to determine if "f" is defind by f(x)=2x^2+5. The problems are f(-2)............next is f(3x)............last is -f(x)............Please, explain the best you can ...i'm lost..the book is useless with explanations
just plug in -2 in the first one as it says "f(-2)"...in place of x & u will get the answer:) its simple:)
Wow, so i was right. Woohoo..
and similarly for the rest...if it says f(3x) then plug in '3x' in place of 'x' got it?
ohh u were..?? good:)
now i gotta go...bye...hope i helped u:)
i've been at this all night...not sure whats been right and whats been wrong.
ohh..dont worry thats how u learn, right?
ACtually, the one with the negative f...not so sure actually
hmm..np...bye for now:)
-f(x)....how in the world...Is it as simple as just writing that out?
hmmm yupp:)
Thank you sooooooooooo much.
ohhhhh:):) youre welcome:) hope i help u next time too:)
Oh, I have 2 more sets to finish that are different...need to finish them today. I am helping someone who seriously needs the help that will never use this stuff, so i'lm trying my very best to help them. Its very important it gets done right you know.
hmm yeah...but i am really tired:(:( sry:(:( gotta go...next time..
Thank you. Nite.
gud nite:):) n byee
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