3logx=2 I need someone to explain what Im suppose to do??
solve for x. 3*log x = 2. divide by 3 on both sides log x = 2/3. solve for x.
the value of x depends on your base.
What do I need to do to solve for x?
\[\log_{e}x = y \rightarrow x = e ^{y}\]
so there is no answer??
of course there is. I explained how to get x from log x in the previous post.
Thanks for your help. I still dont understand, its just me. Thank you.
log x = 2/3 ==> x = base^2/3. if it is natural log, then base is e. But in this case i think base is 10. so x = 10^2/3
Is there something I should be punching in my caculator to get this answer?
type 10^(2/3) in google
copy and paste that exact phrase
I did that and its giving me an answer of 4.??. I just wanted to know from logx=2/3 if there was something I needed to be doing on my cac. Thanks again.
I dont know what calculator you have. Refer to the calculator instructions.
I understand that. I was just looking for some basic steps to get from logx=2/3 to the answer of 10^2/3. Because I dont know what to do from there. I dont even know what to refer to in my cac, because Im not sure of the next step. BUR, I feel really really dumb, and Im sure Im just bothering you. Thanks
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