Question

y=x^2+2

y=-x+4

SOMEONE PLEASE HELP ME ON THIS

Answer 1

Equate the two equations, and then move everythign to one side so you have x^2+x-2. That factors into (x-1)^2=0, therefore x=1

Answer 2

Y=y, so x^2+2=-x+4
x^2+x-2=0
(x-1)(x+2)=0
x=1 or -2
Y=-x+4
y=-1+4. Or y=-(-2)+4
y=3 or y=6
so, x=1, y=3
or x=-2, y=6

Answer 3

@spaceknight ... after you get that 1 , do i plug that into x to get y ?

Answer 4

&lotsobooks omg thanks . can you like tell me the steps on how you do it

Answer 5

lol oops i factored wrong sorry just listen to lotsobooks

Answer 6

i already solved this problem in the one before...

Answer 7

ok so can i ask you guys another question ? i need help on my entire algebra2 homework

Answer 8

you should try doing your own homework

Answer 9

&spaceknight i have been trying . if i knew how to do thiss i wouldntt be on my laptop asking for help . my teacher is the kind that doesnt like to explain too much .... I NEED HELP

Answer 10

Set both equations equal to one another.
Move all of the terms to the left side of the equation by adding or subtracting the terms on both sides of the equation.
Combine like terms.
Since it is a quadratic equation, you can factor it - use FOIL backwards, sort of.
Once you have the 2 possible values of x, then, you can substitute them back inti either of the original equations - I picked -x+4 since it is the easiest.
Then, calculate the values of y.
Remember to keep the x,y pairs together since they only go with one another.

Answer 11

see i never got instructions like that. ok how about this . im about to show you my next problem. im going to try and solve it by myself to see if i can do it but can you still help me

Answer 12

?

Answer 13

y=6x^2+5x+3
y==x+3

Answer 14

\[6x ^{2}+5x+3=-x+3\]

Answer 15

So far, so good.

Answer 16

ok so it will go like this i thinkk

6x^2+5x+3=-x+3
+x-3 +x-3

hold on i think i messed up

Answer 17

i got 6x^2+6x=0 when i subtracted

Answer 18

That is correct.

Answer 19

so what do i do now ?

Answer 20

In this case, it is easiest to subtract 6x from both sides.

Answer 21

then \[6x ^{2} = -6x ?\]

Answer 22

Right.
Then, divide both sides by 6.

Answer 23

ok so then that is x^2 = -1x

or x^2 = -x ?

Answer 24

Right.
Now, divide both sides by x.

Answer 25

ok so then after that x = -1 ?

Answer 26

Right.
Plug -1 into one of the original equations and solve for y.

Answer 27

so whenever i plug it into the second equation how do i do it ? do i ignore the negative there already is ?

Answer 28

No, keep the negative.
-(-1)+3=

Answer 29

wouldnt that 1 just turn into a positive ?

Answer 30

Right.

Answer 31

ok so it would be 1+3 so y = 4 ?

Answer 32

Yep.

Answer 33

We missed a second solution when I had you subtract 6x from both sides.

Answer 34

you are AWESOMEEEE !!!! :p thanks for helping meee

Answer 35

what step did we miss ?

Answer 36

Not a step so much as another solution.
At 6x^2+6x=0, it would have been better to factor 6x out.
So, 6x (x+1)=0
x=-1 or x=0.
then, y=4 or y=3.

Answer 37

You're welcome! Have fun!

Answer 38

:)