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need help with this calc problem using substitution. 3 sqrt 2-x over x exp7. thks
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use the equation toolbox and write out the equation. What you described is unclear.
ok \[ \int\limits_{1}^{2} \sqrt[3]{2-6} / x^{7}\]
this is integration?
sorry.. forgot the dx
okay. so take out the cuberoot(2-6) outside the integral. you will have \[\sqrt[3]{2-6} \int\limits_{1}^{2}x ^{-7}dx\]. That is fairly straightforward to solve
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