A fitnss club charges members a monthly fee and a fee for each fitness class attended. Last month, one member attended 8 fitness classes and paid $80. Another member attendd 14 fitness classes and paid $98. Determine the monthly fee and the fee per fitness class.

Question

anonymous · Answer

So there's a monthly fee (let's call it 'F') and there's fixed per-class-fee (how about 'C' ?)

1st mameber attends 8 classes and pays $80 - so: $$8 C + F = $80$$
2nd member attends 14 classes and pays $98 - so: $$14 C + F = $98$$

so you got two equations in two unknowns. Think you can solve it on your own?

anonymous · Answer

no, please help through the rest :P

anonymous · Answer

Use system of elimination to solve for C.

-1*(8C + F) = -1*($80)                      *Multiply by -1 to eliminate F once you add the 
     (14C + F) = $98                              equations together

So, you now have:

    6C = 18 which means C = 3.           *Plug those values into the original equations
                                                           to solve for F.

I hope that helps.

anonymous · Answer

yes it did actually, thanks a ton! =)