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Mathematics 24 Online
OpenStudy (anonymous):

rationalize the denominator and simplify squre root of 121/5

OpenStudy (anonymous):

11sqrt5/5

OpenStudy (anonymous):

y ? i know 11 comes out twice so its taken out of the sqrt then five remains on the bottom how does it get to the top? gosh im confusing myself

OpenStudy (anonymous):

you will have a square root of 5 on the bottom. In order to get rid of that you multiply the top and bottom by square root of 5. resulting in dhatraditya's answer

OpenStudy (anonymous):

if you multiply a square root by a square root you will cancel the roots and just end up with the number.. so sq root of 5 x sq root of 5 = 5

OpenStudy (anonymous):

what abigail2010 said.

OpenStudy (anonymous):

awesome thanks a bunch

OpenStudy (anonymous):

np =)

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