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how to find the domain for xsquareroot(4-x^2)?
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well, 4-x^2 cant be less than zero.
sqrt(-#) is verbotten
4-x^2 >= 0 -x^2 >= -4 x^2 <= 4 x <= +- sqrt(4) x <= -2 and x <=2 but its wise to double check ;)
Dom: [-2,2] looks about right to me
<........-2............2............> - 0 + 0 - are our results right?
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\[-2lex \ge\]
oops dw about that i pressed s9mething wrong
THANK YOU AMISTRE64
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