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Find the standard form of the equation of the line that passes through the points (-1,-1) and (3,4)
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Did you find the slope of the line?
no
Do you know the formula for the slope?
x1-y2 X2 -Y2 ?
y1
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Not quite. \[Slope =\frac{\text{Change in y}}{\text{Change in x}} = \frac{y_2-y_1}{x_2-x_1}\]
so the slope is 3/5?
5/4
\[\frac{4-(-1)}{3-(-1)}\]
so then what is my standard form equation?
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Once you have the slope, you can plug that into the point slope formula. \[y-y_1 = M(x-x_1)\] Where M is the slope.
And \(x_1,y_1\) are the x and y values of a point on the line (you can pick either point for this)
i give up
Why? You were doing fine so far.
You found M = 5/4
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You are given the x and y values for 2 points, just pick one and plug them in.
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