Question

use ratio test to determine if converge or diverge sigma n=1 to infinity 1/ne^n. after solving it this is where i am stuck n/(n+1)e

Answer 1

lim n->inf (n/ [(n+1)*e] ) = (1/e)* lim n->inf ( n/(n+1) ) = 1/e
1/e < 1/2 <1 and therefore it converges

Answer 2

wouldn't u get infinity over infinity when u plug in n

Answer 3

oh when u factor 1/e and u get 1 when u take the rest of the equation to infinity

Answer 4

exactly

Answer 5

k ty u i get it