Question

Solve differential equation using inverse laplace transform: y''+2y'-3y=6e^(-2t)

Answer 1

I end up doing a partial fraction decomposition and get -3e^(-2t) + 11/2e^(-3t) - 3/2e^t, which is almost right except the actual answer is -2e^(-2t) + 11/2e^(-3t)-3/2e^t. I can't figure out what I'm doing wrong

Answer 2

y(0)=? and y'(0)=?

Answer 3

Oh, sorry. y(0)=2 and y'(0)=-14

Answer 4

this is answer

Answer 5

thank you, i found the mistake i made in my work by comparing.