Question

1. P=2L+2w p=700 meters w= .75 x L 700/4 sides 175 =4 equal sides i substituted 150 in for w. then subed 200 in for L
L= 200 W= 150

2.The width of my computer room is _____% of its length. If the perimeter is 52 feet, then what are the length and width?

Answer 1

TIANA

Answer 2

can you format that to something readable by the rest of us :)

Answer 3

it is a discussion topic i have to answer that is what is given

Answer 4

1. Solve the following problem. The width of a rectangular lot is 75% of its length. If the perimeter is 700 meters, then what are the length and width?

Answer 5

P=2l+2w is the perimeter of a rectangular room.

P=700 width is 3/4 of the lenght...

Answer 6

700 = 2l + 6l/4

Answer 7

I'm not sure what the question is in the first one...because i think you solved it...
for the second question
let L = length
let W = width
let x = percentage (ie 5%, then x would be 0.05)

W = L*x
2W + 2L = 52
substitute
2(L*x) + 2L = 52
L*x + L = 26
L ( x + 1) = 26
L = 26 / (x+1)
W = (26*x) / (x+1)

Answer 8

700 = 14l/4

280 = 14l

280/14 = l

l = 140/7 = 120

Answer 9

tina

Answer 10

l = 700; w = 350/4 if we go the top route and thats after I fixed my glaring fauxpas :)

Answer 11

DOH!.....

Answer 12

i think i just had a lobotomy :)

Answer 13

l=200; w=150

Answer 14

whats with number 2?

Answer 15

# 2 is me having to measure a room and make up an equation for someone else to solve or do you mean the 2L 2W

Answer 16

hmmm... then say the length is 100% of the width and make it a square ;)

Answer 17

52/4 = 13....that was EASY!! lol

Answer 18

amistre plz helo me write that essay its do tommorwo

Answer 19

cant be a square has to be rectangluar

Answer 20

a square IS a rectangle

Answer 21

amistre plz

Answer 22

by definition a square is a rectangle; just a special rectangle

Answer 23

ok so what is the answer you confused me

Answer 24

mary, I dont write esssays; at least not well. And I aint got the time to do no reasearchand put the stuff together if I did.

Answer 25

You wanted to make up a question to fit the ...thing.. in Q2 right?

Answer 26

if p=52 and the width is 100% of the l then l and w are 13

Answer 27

Q1 and Q2 are for my discussion thread it belongs to another student that I have to answer, Pt.2 is i have to do the same for him to answer

Answer 28

then put in 100% as the answer :)

"The width of my computer room is __100___% of its length. If the perimeter is 52 feet, then what are the length and width?"

Answer 29

l=13 ; w=13

Answer 30

ok gottcha

Answer 31

1. Solve the following problem. The width of a rectangular lot is 75% of its length. If the perimeter is 700 meters, then what are the length and width?

2. Measure the length and width of any rectangular (not square) room in your residence, and calculate the perimeter. Determine what percent of the length the width of the room is. Write a problem following the format below and post it for your classmates to solve.
The width of my (living room, family room, etc) is ____% of its length. If the perimeter is ____ meters, then what are the length and width?
Due by 11:59 MST on Friday.

3 Pick a problem posted by your classmate and solve it either by substitution or elimination. Make sure to pick the problem not solved by somebody else and show all steps in the solution. Explain why you chose the method you did.
Due by 11:59 MST on Sunday.

Answer 32

i know thats alot but this is the assignment so u helped me answer the students which is number 3

Answer 33

percent is figured out by taking the "part" and dividing by the "total"; times 100.

35/100 = .35

.35 * 100 = 35% :)

Answer 34

if the length is 144 and the width is 98: the percentages are:

l/w = .xxx times 100 = xx.x%

Answer 35

what is #1

Answer 36

L=200; W=150 is #1

Answer 37

ok i have to show my work

Answer 38

W = (.75)L

700 = 2(.75L) + 2L

700 = 1.5L +2L

700 = 3.5L

700/3.5 = L

L = 200. W = .75(200) = 150

Answer 39

so number 2 says NOT a square...what a crock !

Answer 40

pick a number....

Answer 41

between 1 and 15

Answer 42

7

Answer 43

does 7 work

Answer 44

r u there

Answer 45

im here.. :) got side tracked

Answer 46

....butterfly......>>>>>

Answer 47

i love butterflies all my tats are

Answer 48

7 is fine; say 7 is the width and times that by 4; 28

28 is my length; and my width is 25% of the length

Answer 49

14+56 = 70 is the perimeter of my room....

Answer 50

i aint got any tats. im a good Mormon, most of the time :)

Answer 51

ive got 3

Answer 52

The width of my room, is 25% of its length. If the perimeter is ____ meters, then what are the length and width?
the perimeter is how many meters 70?

Answer 53

70..yes/ 7+7+28+28 = 14+56 = 70

Answer 54

ok i get it

Answer 55

hey r u there amistre64? yesterday you helped me with this
The width of my room, is 25% of its length. If the perimeter is 70 meters, then what are the length and width?
was that 70meters or 70 ft
this is my teacher response
Please check your measurements. First, the ratio of the width to the length is too small. Your room must very narrow. Second, the perimeter of 70 meters appears to be to big for a room in a residence. Is it in meters or feet?