Question

The sum of the squares of two consecutive odd integers is 74. Find the two integers.

Answer 1

odd integer can be represented as 2n+1 and the next odd int would 2n+3 so you have:
(2n+1)^2 + (2n+3)^2 = 74
solve for n

Answer 2

i dont understand it..

Answer 3

i dont remember how to solve n

Answer 4

hmm i guess an easier way is to look at perfect squares and which ones add up to 74
1,3 = 1^2 + 3^2 = 10
3,5 = 3^2 + 5^2 = 34
....

Answer 5

so its 3 and 5?

Answer 6

just remember when you find it that their negative counterparts are answers too because we square them
-5,-3, = (-5)^2 + (-3)^2 = 34
...

Answer 7

no sum of 3 and 5 squared is 34...keep going try 5,7 7,9 9,11
has to equal 74

Answer 8

5 and 7

Answer 9

correct

Answer 10

thank you!

Answer 11

your welcome

Answer 12

Your first method was nicer :( You can't brute force it once you get up to bigboy numbers