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solve 2x^2+12x=-18
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first off add 18 to toehr side, then divide by 2
other*
then factor out wats in the middle.
2(x^2+6x+9)=0
2(x+3)(x+3)=0
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therefore x = -3
hope that helps.
These with non-trivial coefficients are kind of tricky. Rewriting it a comfortable form: 2x^2 + 12x + 18 We can factor a 2 out. 2(x^2 + 6x + 9) Which we can factor into 2(x + 3)(x + 3) So we have two real roots of -3.
so (-3,3) ?
Nope, just two of -3.
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