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Mathematics 14 Online
OpenStudy (anonymous):

How do you put a half-circle into equation form?

OpenStudy (anonymous):

\[x = \sqrt{r^2 - y^2}\] where r is the radius

OpenStudy (anonymous):

thats for the upper half of the circle it's the negative for the bottom half of the circle

OpenStudy (anonymous):

So lets just say that the graph is on (9,0), (0,9), and (-9,0), and those are the dimensions of it. How can I put that into equation form?

OpenStudy (anonymous):

the radius is 9 \[x = \sqrt{81 - y^2}\]

OpenStudy (anonymous):

Thanks!

OpenStudy (anonymous):

no problem

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