Question

4/x+12/x+3=-13

Answer 1

\[\frac{16}{x} + 3 = -13\]
\[\frac{16}{x} = -16\]
-16 x = 16
x = -1

Answer 2

no it' 4 over X and 12 over X+3 = -13

Answer 3

ohh....
so
\[\frac{4}{x} + \frac{12}{x + 3} = -13\]

Answer 4

\[\frac{4(x+3) + 12(x)}{x(x + 3)} = -13\]
cross multiply
4(x+3)+12(x) = -13(x(x+3))

Answer 5

4(x+3)+12(x) = -13(x(x+3))
4x + 12 + 12x = -13x^2 -39x
13 x^2+55 x+12 = 0
(4 + x) (3 + 13 x) = 0
\[x = -4, -\frac{3}{13}\]

Answer 6

yes that's correct
simplyfing rational expressions
I don't understand the last part How did you get (4+x) (3+13x)=0

Answer 7

it's factoring
i should have wrote
(13x + 3)(x + 4)
it might look better this way
but I'm not sure how i can explain factoring.

go to this site
http://tutorial.math.lamar.edu/Classes/Alg/Factoring.aspx
example 3 part e
look it over

Answer 8

Thanks for all yor help

Answer 9

no problem
sorry i can't explain the factoring, but the site is awesome
good luck

Answer 10

It's ok thanks agan I'll check it out