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what is the equation of the line that has a slope of 4 and passes through the point (3, -10)
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Sierra, you need to use the 'point-slope' version of a straight line to work out your equation. That is,\[y-y_1=m(x-x_1)\]where m is your slope and (x_1,y_1) is your given point. So, for you,\[y-(-10)=4(x-3) \rightarrow y+10=4x-12\]so\[y=4x-2\]
u mean y = 4x - 22 right? and thank u sooo much!
Woops, yes, I do. Didn't tap the '2' twice!
haha thank u!
np
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