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Use implicit differentiation to find dy/dx for y^2 = 2xy – x^2
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best way to explain it is to treat y like a variable x .... which gets you: 2 y y'=2xy'+y-2x
2yy'=2xy'+2y-2x
Solve the above for y' and u are done
yea that forgot some brackets
is the 2yy 2y^2?
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?I dont understand the question
is the 2yy you wrote suposed to be 2y^2
I think you are talking about 2yy' this does not equal 2yy
okay I got 2y-2x
do you know how to solve this equation for x: x+4=2x-3
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2yy'-2xy'=2y-2x y'(2y-2x)=2y-2x y'=1
Eric is right
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