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Mathematics 11 Online
OpenStudy (anonymous):

how do i solve a a problem like this? plz explain in detail

OpenStudy (anonymous):

\[\sqrt{3x+4} = 1 + \sqrt{3x-11}\]

OpenStudy (anonymous):

square both sides first

OpenStudy (anonymous):

3x+4 = 1+3x-11 +2(3x-11)^1/2

OpenStudy (anonymous):

but then how do I get rid of the radical so I can solve for x?

OpenStudy (anonymous):

14=2(3x-11)^1/2 7= (3x-11)^1/2 squaring again we get

OpenStudy (anonymous):

49=3x-11 3x=60 x=20

OpenStudy (anonymous):

oh I see...thanks!

OpenStudy (anonymous):

good one !!

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