Question

Suppose that at the end of any given year an automobile is only worth 80% of it's value a the beginning of that year. If a car cost 21,000 new, what is it's value at the end of five years?

Answer 1

21000*(1-0.8)^5

Answer 2

ignore that post sorry

Answer 3

lol.

Answer 4

21000*(0.8^5)
:)

Answer 5

1st yr .8x$21000=$16800
2nd yr .8 x 16800=13440
3rd yr .8 x 13440=10752
4th yr .8 x 10752=8601.60
5th yr .8 x 8601.60=$6881.28

Answer 6

hmmmmm...........

Answer 7

Or as dumbcow stated\[21000*.8^{5}\]

Answer 8

BAM! both of you two were right! I just had to round down. Thanks so much on this one guys!

Answer 9

A company offers a starting yearly salary of 31,000, with raises of 2,000 per year. Find the total salary over a ten-year period.

Answer 10

Something tricky about this one, it's like 300k, or 400k sumthin...

Answer 11

First find salary at end of ten-year period
A10 = 31000+(10-1)*2000
A10 = 49000
Then use series sum formula
Sum = 1/2*n*(A1+A10)
Sum = 1/2*10*(31000+49000)
...

Answer 12

.......

Answer 13

thats left for you to compute ;)

Answer 14

I am a bottom line kind of girl..... :)

Answer 15

It doesn't add up.......hmmm...

Answer 16

Sigh....

Answer 17

what did you come up with?

Answer 18

Hello.

Answer 19

Ah well.......I came up with a bunch of letters I don't understand.

Answer 20

what do you mean?
Sum = 1/2*10*(31000+49000)
sum= 5*(80,000) = 400,000

Answer 21

....

Answer 22

SO it's 400k + 80k?

Answer 23

where did the 80k come from?

Answer 24

31+49

Answer 25

So it's 400K even?

Answer 26

BINGO!

Answer 27

yes
sorry for the confusion

Answer 28

Can you help the other Kelley? Same question, different numbers. Like 6 people are trying it now, and can't help her get this question!

Answer 29

um yeah