Suppose that at the end of any given year an automobile is only worth 80% of it's value a the beginning of that year. If a car cost 21,000 new, what is it's value at the end of five years?
21000*(1-0.8)^5
ignore that post sorry
lol.
21000*(0.8^5) :)
1st yr .8x$21000=$16800 2nd yr .8 x 16800=13440 3rd yr .8 x 13440=10752 4th yr .8 x 10752=8601.60 5th yr .8 x 8601.60=$6881.28
hmmmmm...........
Or as dumbcow stated\[21000*.8^{5}\]
BAM! both of you two were right! I just had to round down. Thanks so much on this one guys!
A company offers a starting yearly salary of 31,000, with raises of 2,000 per year. Find the total salary over a ten-year period.
Something tricky about this one, it's like 300k, or 400k sumthin...
First find salary at end of ten-year period A10 = 31000+(10-1)*2000 A10 = 49000 Then use series sum formula Sum = 1/2*n*(A1+A10) Sum = 1/2*10*(31000+49000) ...
.......
thats left for you to compute ;)
I am a bottom line kind of girl..... :)
It doesn't add up.......hmmm...
Sigh....
what did you come up with?
Hello.
Ah well.......I came up with a bunch of letters I don't understand.
what do you mean? Sum = 1/2*10*(31000+49000) sum= 5*(80,000) = 400,000
....
SO it's 400k + 80k?
where did the 80k come from?
31+49
So it's 400K even?
BINGO!
yes sorry for the confusion
Can you help the other Kelley? Same question, different numbers. Like 6 people are trying it now, and can't help her get this question!
um yeah
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