Question

The diagonal of a square A is (x+y). The diagonal of a square B with twice the area of A is

Answer 1

if you had a square that was 4 by 4 that are would be 16
the diagonal would be 4^2 + 4^2 = c^2
16 + 16 = c^2
c = sqrt(32)
c = 4sqrt(2)

a square with double that area would have an area of 32
each side would be sqrt(32) = 4sqrt(2)
the diagonal would be (4sqrt(2))^2 + (4sqrt(2))^2 = c^2
32 + 32 = c^2
c = sqrt(64)
c = 8

the ratio is 8
--
4sqrt(2)

which is sqrt(2) larger

so sqrt(2)(x + y)

Answer 2

correct answer