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the integral of [sin(x)/x]dx, solved using series...
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reimann series right?
i was thinking a power series
and that sigma summation sign and i?
well yeah
is this one of those ones that you have to put into an equality?
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like between -1 and 1, since it's a sine?
power series, the term is familiar; this stuff?\[\sum_{} i^2 = \frac{n(n+1)(2n+1)}{6}\]
1/(1-x) =\[\sum_{?}^{?}x^n\]
wow im bad at the equation editor... sorry guys.
charles xaviers here; hell know ;)
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Well sin(x)=x-x^3/3!+x^5/5!-x^7/7!+x^9/9!... I would divide by x. Then integrate and try to find a sigma representation.
maclaurin series?
Yeah
oh very clever! thank you.
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