Mathematics
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OpenStudy (anonymous):
what is a solution for the equation 2^n=10?
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OpenStudy (anonymous):
Did you try taking the square root?
OpenStudy (anonymous):
Margaret?
OpenStudy (anonymous):
Am I missing something? Why would you take the square root... ?
OpenStudy (anonymous):
To get the value of n that yields 10.
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OpenStudy (anonymous):
take the square root and then..?
it doesnt work
OpenStudy (anonymous):
Ack! dislexia
OpenStudy (anonymous):
Don't worry, your answer was still more helpful than Mr. Wolfram's
OpenStudy (anonymous):
Take the log
OpenStudy (anonymous):
im confused
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OpenStudy (anonymous):
I read it as \(n^2\) not \(2^n\) I need my exponents small and above, that flat representation plays hell with my dislexia.
OpenStudy (anonymous):
Take the log of both sides.
OpenStudy (anonymous):
Take the logarithm of both sides (ln or log for calc friendly) to knock that n down.
OpenStudy (amistre64):
log10 right?
OpenStudy (anonymous):
Log is much more friendly since it's a 10 on the other side
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OpenStudy (anonymous):
But any log will do.
OpenStudy (anonymous):
would the answer be.. n=10/log2?
OpenStudy (anonymous):
No, you forgot to take the log of 10 also.
OpenStudy (anonymous):
soo.. n=1/log2?
OpenStudy (anonymous):
I wish that in addition to medals they'd let us award slaps for people who give half-assed answers and wander off ;p
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OpenStudy (anonymous):
Yes precisely!
OpenStudy (anonymous):
so i got it!!?? :)
OpenStudy (anonymous):
You did! =)
OpenStudy (anonymous):
thankyou for your help
OpenStudy (anonymous):
You're very welcome.