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Mathematics 18 Online
OpenStudy (anonymous):

what is a solution for the equation 2^n=10?

OpenStudy (anonymous):

http://www.wolframalpha.com/input/?i=2^n+%3D10

OpenStudy (anonymous):

Did you try taking the square root?

OpenStudy (anonymous):

Margaret?

OpenStudy (anonymous):

Am I missing something? Why would you take the square root... ?

OpenStudy (anonymous):

To get the value of n that yields 10.

OpenStudy (anonymous):

take the square root and then..? it doesnt work

OpenStudy (anonymous):

Ack! dislexia

OpenStudy (anonymous):

Don't worry, your answer was still more helpful than Mr. Wolfram's

OpenStudy (anonymous):

Take the log

OpenStudy (anonymous):

im confused

OpenStudy (anonymous):

I read it as \(n^2\) not \(2^n\) I need my exponents small and above, that flat representation plays hell with my dislexia.

OpenStudy (anonymous):

Take the log of both sides.

OpenStudy (anonymous):

Take the logarithm of both sides (ln or log for calc friendly) to knock that n down.

OpenStudy (amistre64):

log10 right?

OpenStudy (anonymous):

Log is much more friendly since it's a 10 on the other side

OpenStudy (anonymous):

But any log will do.

OpenStudy (anonymous):

would the answer be.. n=10/log2?

OpenStudy (anonymous):

No, you forgot to take the log of 10 also.

OpenStudy (anonymous):

soo.. n=1/log2?

OpenStudy (anonymous):

I wish that in addition to medals they'd let us award slaps for people who give half-assed answers and wander off ;p

OpenStudy (anonymous):

Yes precisely!

OpenStudy (anonymous):

so i got it!!?? :)

OpenStudy (anonymous):

You did! =)

OpenStudy (anonymous):

thankyou for your help

OpenStudy (anonymous):

You're very welcome.

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