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solve for x: 2^x+1=8^x-2
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Is that 2^(x+1)?
yes
Note you can write 8 as 2^3. Try using that
so x=3/2?
No. How did you come to that answer?
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reducing? im really not good at math
So we can substitute 2^3 for 8 right. It becomes 2^(x+1)=[2^3]^(x-2). The right hand side can be simplified 2^(x+1)=2^3(x-2) Since the bases are the same, the exponents must be equal.
x would = 2
Did you equate the exponents: Like if i say a^x=a^y, x must be equal to y. So in our case x+1=3(x-2)
x=7/2?
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Yes. Do you see how the substitution helped? It made the bases the same so we can conclude that the exponents are equal
yes you smart cookie. thankyou!!
:) Np
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