The population P in 1997 for a state is given along with r, it's annual percentage of continuous growth.
P=33 millions, r=1.7%
(a) Write the formula f(x) =P erx, where r is in decimal notation, that model the population in millions x years after 1997
(b)Estimate the population in 2015

Question

The population P in 1997 for a state is given along with r, it's annual percentage of continuous growth.
P=33 millions, r=1.7% 
(a) Write the formula f(x) =P erx, where r is in decimal notation, that model the population in millions x years after 1997
(b)Estimate the population in 2015

amistre64 · Answer

r = .017

amistre64 · Answer

33,000,000 e^(.017*1000000(x))

anonymous · Answer

........

anonymous · Answer

33? Wth?

anonymous · Answer

Newton?

anonymous · Answer

33 million is written out there.

anonymous · Answer

that doesnt make sense

anonymous · Answer

The formula says Perx which is usually just an abbreviation for f(x)=Pe^(rx)

amistre64 · Answer

its your question, not mine ;)   im just the messenger....of doom!!

amistre64 · Answer

do we have to use millions of years to find 2015?

anonymous · Answer

Dude, I have no clue, lol. That doesn;t make sense.

amistre64 · Answer

why dont it make sense?

amistre64 · Answer

large numbers are allowed to exist ;)

amistre64 · Answer

or maybe it means:

Write the formula f(x) =P erx, where r is in decimal notation, that model the population (in millions);  x years after 1997

amistre64 · Answer

33,000,000 e^(.017x)

amistre64 · Answer

33 e^(.017x)  seems more reasonable then.... if I parse the question correctly

amistre64 · Answer

x = 18...(2015)

   33 * (e^(.017 * 18)) = 44.8134161 million

anonymous · Answer

it wasn;t right....... :(

amistre64 · Answer

which one, the 33 e^(.017x) ?  cause that seems to be the most logical one

anonymous · Answer

correct answer was...........

anonymous · Answer

33e^0.017x

anonymous · Answer

33 million wasn't correct either
ARGHH!

amistre64 · Answer

:)  whats the correct answer then

anonymous · Answer

44.8

anonymous · Answer

Ready for same problem, new numbers?

amistre64 · Answer

I got that for b already

anonymous · Answer

you said 33 mil

amistre64 · Answer

no, I said 33 million was how you set the problem up; not the answer; you gave a 2 parter. :)

anonymous · Answer

:(

amistre64 · Answer

part 1:  set up an equation to use with this info:  33 e^(.017x)

part 2) use it to find the population in 18 years

amistre64 · Answer

33 million was part of the setup; in part 1.

anonymous · Answer

The population P in 1991 for a state is given along with r, it's annual percentage of continuous growth.
P=34 millions, r=2.3% 
(a) Write the formula f(x) =P erx, where r is in decimal notation, that model the population in millions x years after 1991
(b)Estimate the population in 2016

amistre64 · Answer

PART A :)  34 e^(.023x)

PART B ;)  

2016-1991 = 25

34 * (e^(.023 * 25)) = 60.4224379

anonymous · Answer

that wasn't it! nooooooooooo

anonymous · Answer

I'm shocked!

amistre64 · Answer

that should be it unless google lied to me in the math..

anonymous · Answer

That formula should be correct?

amistre64 · Answer

60.4224379.... is the same answer I get on the calculator

amistre64 · Answer

I used the formula they gave you and the numbers.... there isnt really a way to mess that up :)  even for me...

amistre64 · Answer

60.4 maybe is what they want

anonymous · Answer

I was trying the formula first the .......34 e^(.023x)

anonymous · Answer

for A

amistre64 · Answer

i dont know how they want it formated; thats a computer program issue, but the formula itself is good

anonymous · Answer

aw nuts.

anonymous · Answer

it was 0.023

amistre64 · Answer

....those bastards!.... they killed kenny

anonymous · Answer

second part was right! ;)