The population P in 1997 for a state is given along with r, it's annual percentage of continuous growth. P=33 millions, r=1.7% (a) Write the formula f(x) =P erx, where r is in decimal notation, that model the population in millions x years after 1997 (b)Estimate the population in 2015
r = .017
33,000,000 e^(.017*1000000(x))
........
33? Wth?
Newton?
33 million is written out there.
that doesnt make sense
The formula says Perx which is usually just an abbreviation for f(x)=Pe^(rx)
its your question, not mine ;) im just the messenger....of doom!!
do we have to use millions of years to find 2015?
Dude, I have no clue, lol. That doesn;t make sense.
why dont it make sense?
large numbers are allowed to exist ;)
or maybe it means: Write the formula f(x) =P erx, where r is in decimal notation, that model the population (in millions); x years after 1997
33,000,000 e^(.017x)
33 e^(.017x) seems more reasonable then.... if I parse the question correctly
x = 18...(2015) 33 * (e^(.017 * 18)) = 44.8134161 million
it wasn;t right....... :(
which one, the 33 e^(.017x) ? cause that seems to be the most logical one
correct answer was...........
33e^0.017x
33 million wasn't correct either ARGHH!
:) whats the correct answer then
44.8
Ready for same problem, new numbers?
I got that for b already
you said 33 mil
no, I said 33 million was how you set the problem up; not the answer; you gave a 2 parter. :)
:(
part 1: set up an equation to use with this info: 33 e^(.017x) part 2) use it to find the population in 18 years
33 million was part of the setup; in part 1.
The population P in 1991 for a state is given along with r, it's annual percentage of continuous growth. P=34 millions, r=2.3% (a) Write the formula f(x) =P erx, where r is in decimal notation, that model the population in millions x years after 1991 (b)Estimate the population in 2016
PART A :) 34 e^(.023x) PART B ;) 2016-1991 = 25 34 * (e^(.023 * 25)) = 60.4224379
that wasn't it! nooooooooooo
I'm shocked!
that should be it unless google lied to me in the math..
That formula should be correct?
60.4224379.... is the same answer I get on the calculator
I used the formula they gave you and the numbers.... there isnt really a way to mess that up :) even for me...
60.4 maybe is what they want
I was trying the formula first the .......34 e^(.023x)
for A
i dont know how they want it formated; thats a computer program issue, but the formula itself is good
aw nuts.
it was 0.023
....those bastards!.... they killed kenny
second part was right! ;)
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